Alr 9680 Dev C
Usually this space is used by the file system itself.Large amounts of hidden disk space may also indicate errors in the file system. You can see this hidden space as “other volumes” in About This Mac or in Disk Utility. Daisydisk purgeable space. This is normal. Note that even if you don’t create additional volumes yourself, there can be hidden small volumes used by macOS itself.A free update of DaisyDisk is coming up soon, that will reflect all the above High Sierra & APFS changes!Note that some small amount of hidden space (a few GB) may still remain even after scanning as administrator.
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What is the c++ code runnable in dev c++ developmental tool, for this output????(it will be like this if the number of amount of string is an even number. and prints like a shape of a hour glass)
enter string: ccss
c c
c
s
s s
enter string: ccss
c c
c
Alr 9680 Dev Company
s
s s
(it will be like this if the number of amount of string is an odd number)
enter string: table
t t t
a a
b
l l
e e e
(note: it should be 3 strings to be accepted as input(string) in this program)
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What is the c++ code runnable in dev c++ developmental tool, for this output????
what is the c++ code runnable in dev c++ developmental too, for this output????
it will accept a string and creates a figure, like in the following:
Alr 9680 Dev C Reviews
(it will be like this if the number of amount of string is an even number. and prints like a shape of a hour glass)enter string: ccss
c c
c
s
s s
What is the c++ code runnable in dev c++ developmental tool, for this output????
do an if mod 2 on the string length to figure out if it is even or odd, if it is even generate two strings from the original by going from 0 to length/2 and length/2 to length.
For output cout from within 2 loops, one after the other, the first loop dealing with the first substring, the second loop dealing with the second substring.
The loop will simply start at the length of the substring and decrement to 0, each time printing length number of characters from the substring to the screen.
The second loop will do the same but in reverse, starting at 1 and stoping at length.